What would this look like in C++ code?

Write a program that reads ten numbers (in an array), and counts the number of elements in the array that are divisible by 3.

What would this look like in C++ code?
#include %26lt;iostream%26gt;


using namespace std;


int main( int, char **)


{


int i, ary[10];


for (i = 0; i %26lt; 10; ++i)


cin %26gt;%26gt; ary[0];


int cnt = 0;


for (i = 0; i %26lt; 10; ++i)


{


if (ary[i] % 3 == 0)


++cnt;


}


cout %26lt;%26lt; cnt %26lt;%26lt; endl;


return 0;


}
Reply:all numbers are divisible by 3. No need to load them into an array.
Reply:It could look very similar to a program written in C to do the samething. Shouldn't you do your own homework? At lease give it a try and ask for help.





Actually - I've seen someone earlier posting a nearly complete program to do the same thing but having problems withit.

chrysanthemum