Write a c code to display the following pattern?

1


2 3


4 5 6


7 8 9 10

Write a c code to display the following pattern?
Let’s index lines from 1 to N. In the n-th line, there are n elements ending to n(n+1)/2.


We can write a function PrintLine(int n) which prints the n-th line like:





void PrintLine(int n)


{


int last = n * (n + 1) / 2;





for (int k = 0; k %26lt; n; k++)


printf (“%d\t”, last – k);





printf (“\n”);


}





Now we can use PrintLine () in our main:





main()


{


int N;


printf (“Enter N: “);


scanf(“%d”, %26amp;N);





int n;


for (n = 1; n %26lt;= N; n++)


PrintLine (n);


}





--------------------------------------...


Oops! Correction: the for loop in PrintLine():





for (int k = 1; k %26lt;= n; k++)


printf (“%d\t”, last – n + k);
Reply:for(i=0;i%26lt;4;i++)


{


for(j=0;j%26lt;=i;j++)


print j+1


}


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Reply:The absence of ellipsis (…) makes it too easy! Just use four printf (C) or cout %26lt;%26lt; … (C++) lines!
Reply:hint: use a loop
Reply:#include %26lt;stdio.h%26gt;





void main()


{


int temp=3;


for(int i = 1, j = 1; i %26lt;= 10; i++)


{


printf("%d ", i);


if(i==j)


{


printf("\n");


j = temp;


}


temp = i+j+1;


}


}
Reply:printf ("1\n2 3\n4 5 6\n7 8 9 10\n");





But thats not the answer you want.

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