Correct this c++ code?

void main(){


int x=5;


int y=0;


try{


cout%26lt;%26lt;x/y;


}


catch{


cout%26lt;%26lt;"cannot devide by zero";


}





}


//the problem is the catch block

Correct this c++ code?
try - C++ keyword that denotes an exception block (You had this correct)


catch - C++ keyword that "catches" exceptions (you needed to add the variable type parameter)


throw - C++ keyword that "throws" exceptions (You needed to put a throw statement in to activate if you were "dividing by zero"





EDIT: I initialized the divide variable to zero, the program works fine when I compile it, try re-building the solution, if it still doesn't work, I'd have to take a look at what compiler your using (which you didn't mention) to find out what the problem is. OR at least describe your error. Regardless I doubt your compiler would reject integer division, which is the only thing I could think of at the current time that would cause a crash, but I haven't used every compiler yet.





EDIT: I did a minor rewrite of the program, try it now.


#include %26lt;iostream%26gt;


using namespace std;


int main()


{


int x=5;


int y=0;


int divide;


try


{


x/y;


throw 1;


}


catch(int a)


{


cout%26lt;%26lt;"cannot devide by zero" %26lt;%26lt; endl;


system("pause");


return 1;


}


divide = x / y;


cout %26lt;%26lt; divide;


system("pause");


return 0;


}
Reply:I think you might try to put the paranthesis () at the end of the catch before braces{...}





Try it and have a good luck.
Reply:You need to tell C++ ,the type of exception that you want to catch. This is done as follows :


try{


/** Your try code block goes here */


}


catch(Exception e){


/** Your catch code block goes here */


}





Here Exception is the base exception class(superclass).





Try this, it should work.