I keep getting e = 1.0000000000 when I try to approximate e with the following C code in Dev-C++:?

#include %26lt;stdio.h%26gt;


#include %26lt;math.h%26gt;





int main()


{


int x;


double y, e;





printf("How much precision?\n");


scanf("%d", %26amp;x);


getchar();





y = 1 + (1 / x);


e = pow(y, x);





printf("e = %f\n", e);


getchar();


}





I am using the limit function to find e, which is (1+(1/n))^n, not the series function which is 1/n!. What is wrong with this code? It makes perfect sense to me.

I keep getting e = 1.0000000000 when I try to approximate e with the following C code in Dev-C++:?
Try changing:





y = 1 + (1 / x);





to:





y = 1.0 + (1.0 / x);





and declaring x as a double precision variable and seeing if it makes a difference. You might have a automatic casting problem. The following code worked for me:





1 #include %26lt;stdio.h%26gt;


2 #include %26lt;math.h%26gt;


3


4 int main(void)


5 {


6


7 double x, y, e;


8


9 printf("How much precision?\n");


10 scanf("%lf", %26amp;x);


11 getchar();


12


13 y = 1 + (1 / x);


14 e = pow(y, x);


15


16 printf("e = %f\n", e);


17 getchar();


18 }





The problem is integer division. If I declare





int x;





and then do something like:





y = 1 + 1/x;





the expression 1/x evaluates to zero. To that we add one, then we cast y as a double precision value so it is displayed as a floating point number.